why i get this error when using integral?

Error using integralCalc/finalInputChecks (line 515) Output of the function must be the same size as the input. If FUN is an array-valued integrand, set the 'ArrayValued' option to true.
Error in integralCalc/iterateScalarValued (line 315) finalInputChecks(x,fx);
Error in integralCalc/vadapt (line 132) [q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 75) [q,errbnd] = vadapt(@AtoBInvTransform,interval);
Error in integral (line 88) Q = integralCalc(fun,a,b,opstruct);
T = 5;
t = linspace(0,5*T,5*500+1); % 5 cycles
t = t(1:end-1);
n = (1:3).';
a0 = (1/T) * integral(@(t) exp((10 - t) / 2), 0, 5);
an = (2/T) * integral(@(t) exp((10 - t) / 2).*cos(2*pi*f0*n*t), 0, 5);
the error occurs when computing an
even when i try the time vector without multiplying by 5. the same problem occurs

 Akzeptierte Antwort

Torsten
Torsten am 27 Mär. 2018

4 Stimmen

The solution is given in the error message:
an = (2/T) * integral(@(t) exp((10 - t) / 2).*cos(2*pi*f0*n*t), 0, T, 'ArrayValued',true);
By the way: You don't need to specify the t-vector ; "integral" will use ist own spatial gridding.
Best wishes
Torsten.

1 Kommentar

Kedar Bahulkar
Kedar Bahulkar am 20 Mär. 2021
Bearbeitet: Kedar Bahulkar am 20 Mär. 2021
Hello, Thankyou @Torsten. I had the same error and it got solved by your answer. I want to know, whether it is necessary to add
...'ArrayValued',true)
when performing numerical integration always?
Thank you
Kedar

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu MATLAB finden Sie in Hilfe-Center und File Exchange

Gefragt:

am 27 Mär. 2018

Bearbeitet:

am 20 Mär. 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by