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If y(j) is less than some number (say 3) then I want to use higher value of k (say 4) but in the range of 5th iteration before and after y becomes 3. For example in 40th iteration y becomes 3. I want to use k=7 from 35th to 45th iteration. Pls help.

1 Ansicht (letzte 30 Tage)
N=100;
dt=0.05;
k=2;
t=zeros(N,1);
y=zeros(N,1);
y(1)=2;t(1)=0;
for j=1:N-1
t(j+1)=t(j)+dt;
y(j+1)=y(j)+dt*(2+k);
end
plot(t,y)
  2 Kommentare
John D'Errico
John D'Errico am 26 Mär. 2018
Bearbeitet: John D'Errico am 26 Mär. 2018
Your question is quite confusing, because the criteria seems to be depend on several things that are not really clear.
Regardless, what stops you from using an if statement to choose k, based on the value of y(j), or iteration, etc?
Dharma
Dharma am 26 Mär. 2018
Thank you John,
My actual code involves sine function. If I impose if condition on y and then use higher value of k ( if y (j) <3 k=4) then many spikes ( means k=4 is taken frequently like spikes) in k vs t plots will be seen. So I am trying to give k=4 for some finite interval of time. But that time interval should be the one in which y goes beyond 3.

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