How to quickly find the position of a value in a sorted column data?

11 Ansichten (letzte 30 Tage)
I have a list of ascendingly sorted data A = [-80, -79.6, -79.2, -77, 65,... 45]. If there is a value B, how do I quickly find the indices of the two values with one smaller than that and the very next one larger than that? For example, if B=79.8, the two indices will be 1 and 2. If B = 78, the two indices should be 3 and 4.
I know how to write a loop to process this, but my database is huge. As a result, it would take a huge amount of time to process.
Thanks!

Akzeptierte Antwort

Star Strider
Star Strider am 14 Mär. 2018
Try this:
V = linspace(-80, 45, 150); % Create Vector
B = -78;
idx = find(V <= B, 1, 'last');
Result = [idx idx+1];

Weitere Antworten (0)

Kategorien

Mehr zu Shifting and Sorting Matrices finden Sie in Help Center und File Exchange

Tags

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by