- Read the documentation on if-else-end
- See Debug a MATLAB Program
- It's good practice to have an else-clause
Error in function at if-elseif
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Raul Vaida
am 10 Mär. 2018
Kommentiert: Raul Vaida
am 10 Mär. 2018
I've got the error Output argument "val" (and maybe others) not assigned during call to "yt". yt(x) funtion:
function [val] = yt(x)
if ((-9<=x) & (x<-3)) | ((3<=x) & (x<=9))
val = sin(5*x);
elseif (-3<=x) & (x<3)
val = cos(x) - cos(3) - sin(15);
end
and i call the function using the following
x = -9:9;
val = yt(x)
I've got no output from this.
1 Kommentar
per isakson
am 10 Mär. 2018
Bearbeitet: per isakson
am 10 Mär. 2018
Akzeptierte Antwort
Ahmet Cecen
am 10 Mär. 2018
Bearbeitet: Ahmet Cecen
am 10 Mär. 2018
x is a vector at this point so your comparisons are not resolving to a single true false. I am guessing this is what you meant to do:
x = -9:9;
val = yt(x)
function [val] = yt(x)
for i = 1:length(x)
if ((-9<=x(i)) && (x(i)<-3)) || ((3<=x(i)) && (x(i)<=9))
val(i) = sin(5*x(i));
elseif (-3<=x(i)) && (x(i)<3)
val(i) = cos(x(i)) - cos(3) - sin(15);
end
end
end
There are better ways to do this of course, but this is probably the easiest to relate.
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