How do I extract the last Time value from a .txt file using regexp?

I have a few hundred files that has header information. An example is as follows:

Measurement: ENERGY

Date: 02/31/2019,02/31/2018

Time: 10:34:51.49,15:21:39.24

Temperature (C): 32.82,8.88,-10.07,32.66,8.94,-10.07

TEC Silicon Temperature (C): 9.90,9.88

Battery Voltage: 7.52,7.41

I want to be able to extract the second time values from each of the files and I have the following extract of code:

filetext = fileread(NameIn);
expr = '(?s)\sTime:\s\d+:\d\d\:\d\d\.+\d+\,(?P<myfield>)+';
time = regexp(filetext, expr, 'once','match')

But, the output is a 0x0 empty char array. What am I doing wrong? :(

Answer 1

[Elias Gule]

For this particular case, the following 'regex' seems to be working:

expr = '(?<=Time\s*:\s*(\d{2}:\d{2}:\d{2}\.\d{2},\d{2}:\d{2}:))(?<your_field>(.*))';
time = regexp(txt, expr, 'names','dotexceptnewline');

When a match is found this will return a struct array with a field named: "your_field".

[BrainOnLunchBreak]

It gives me NaN

[Elias Gule]

ok. try the attached code and text file.