array dimensions must match in binary op
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ABDUL
am 17 Feb. 2018
Beantwortet: Image Analyst
am 18 Feb. 2018
i am trying to implement the SLM for mimo ofdm system i tried implementing it. there is some error can any one help in this regard
N=64; % number of subbands
L=4; % oversampling factor
C=16; % number of OFDM symbol candidates
Nt=2; %number of transmitters
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% phase factor matrix [B] generation
p=[1 -1 1j -1j]; % phase factor possible values
randn('state', 12345);
B=randsrc(C,N,p); % generate N-point phase factors for each one of the
% C OFDM candidates
for ii=1:Nt
for n=1:C
for n1=1:N
B_1(n,:,:)=B(:,:);
end
end
end
ofdm_symbol=randn(100,64,2)+(1j*randn(100,64,2));
for i=1:NN
some instructuions ….
p=[];
for k=1:C
p=[p; B_1(k,:,:).*ofdm_symbol(1:NN,:,:)];
end
end
I am getting the error message as
Error:
Array dimensions must match for binary array op.
p=[p; B_slm(k,:,:).*ofdm_symbol(1:NN,:,:)];
2 Kommentare
Walter Roberson
am 17 Feb. 2018
In your code
for n=1:C
for n1=1:N
B_1(n,:,:)=B(:,:);
end
end
neither your left hand side of the assignment nor the right hand side of the assignment depend upon n1, so it is not clear why you have the for n1 loop there?
Akzeptierte Antwort
Image Analyst
am 18 Feb. 2018
In a 3D array, let's call the first index rows, the second index columns, and the last index slices. So when you do
B_1(k,:,:).*ofdm_symbol(1:NN,:,:)
even if the last two indexes are the same size, in the B_1 array you're taking one row, while in the ofdm_symbol array, you're taking NN rows. So unless NN = 1, you're not multiplying the same number of elements, which you must to be a valid element-by-element multiplication.
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