Using normrnd to generate a random sequence

I'm trying to use the function 'normrnd' to generate a zero-mean random sequence distributed uniformly between +/- 0.25. How do I go about doing this?

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Roger Stafford
Roger Stafford am 12 Feb. 2018

1 Stimme

The best answer to your question is, “don’t use ‘normrnd’ for that purpose!” It is very much the wrong distribution for that.
You should use ‘rand’ as follows:
x = 0.5*rand(m,n)-0.25;
This will give you a statistically uniform distribution between -0.25 and +0.25, and nowhere else.

2 Kommentare

John BG
John BG am 12 Feb. 2018
Bearbeitet: John BG am 12 Feb. 2018
Hi Nat
.. to generate a .. random sequence ..
x = 0.5*rand(1,n)-0.25
or
x = 0.5*rand(n,1)-0.25
not m sequences
John BG
Nat
Nat am 12 Feb. 2018
Thanks to both of you for your help!

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Nat
am 12 Feb. 2018

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