How to get the first five minimum number for a list

Hi,

I would like to get the index number of the first five minimum number from the list. This is my code:

list = [4,10,1,2,7,12,5,6,10,8];
min=list(1,1)
ind = 1;
N = length(list)
t= 0;
while (t<5)
    for n = 2:N
        if min>list(n)
            ind=n;
            min=list(n);
        end
    end
    minIndexList(1,t+1) =ind ;
    t = t+1; 
end

disp(minIndexList)

However, the code just stored and repeat the index of the minimum Fors insance, minIndexList just stored >> 3,3,3,3,3. By right, the minIndexList should store = 3,4,1,7,8. Do anyone can help me to solve this problem? Thank you in advance

[Walter Roberson]

What behaviour do you want if the list has duplicates? Are you looking for the indices of the 5 smallest unique values, or the 5 smallest values including duplicates?

What output would you expect for the list [1 1 1 2 2 2 2 3 3 3 3 3 3] ? You "use up" 3 of the output slots for the 1's, so then you have 2 output slots remaining but 4 locations that have the same minimum value: how do you decide which of those 4 locations you give the index of?

Answer 1

[Birdman]

Use the simple code below:

[~,idx]=ismember(sort(list),list);
idx=idx(1:5)

[Walter Roberson]

That is a complicated way of writing

[~, idx] = sort(list);
idx = idx(1:5);

[Birdman]

Yes but still does the job.

[amj]

Thanks a million Birdman & Walter Roberson

Answer 2

[Walter Roberson]

https://www.mathworks.com/help/matlab/ref/mink.html

[~, idx] = mink(list, 5)

[amj]

Thank you Walter Roberson. Yeah ..indeed true. Any idea if the repeating indexes occur?