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one-by-one matrix assignment

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Antonio
Antonio am 6 Feb. 2018
Kommentiert: Antonio am 6 Feb. 2018
I need to find the minimum values in each column of matrix "A", and then replace those min values with the values in last row of matrix "B" (which has same number of columns). Like I have these:
>> A = randi(10,10,5)
A =
3 5 9 5 8
7 6 4 10 2
8 4 1 7 4
4 7 2 8 2
7 5 8 7 5
3 7 10 10 1
5 7 8 5 7
8 3 8 2 3
6 10 2 1 10
3 7 6 7 2
>> B = randi(100,3,5)
B =
10 34 66 18 62
99 95 49 54 81
52 1 52 9 95
>> [M,I] = min(A)
M =
3 3 1 1 1
I =
1 8 3 9 6
And I want to replace the values of "M" with "B(end,:), so that:
A(1,1) = B(end,1);
A(8,2) = B(end,2);
A(3,3) = B(end,3);
A(9,4) = B(end,4);
A(6,5) = B(end,5);
I try "A(I) = B(end,:)" and "A(I(1,:)) = B(end,:)" but they do not work! Any ideas how I could do that? My real matrices are huge (1200x100000) so no way to do it by hand!
  4 Kommentare
Jos (10584)
Jos (10584) am 6 Feb. 2018
ok. then Andrei's answer suffices.
Antonio
Antonio am 6 Feb. 2018
@Jos (10584) great, thanks!

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Andrei Bobrov
Andrei Bobrov am 6 Feb. 2018
Bearbeitet: Andrei Bobrov am 6 Feb. 2018
[~,idx] = min(A);
s = size(A);
A(sub2ind(s,idx,1:s(2))) = B(end,:);

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