how to fix inner matrix dimensions 3D plot?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
sophp
am 1 Feb. 2018
Beantwortet: Star Strider
am 1 Feb. 2018
I am trying to plot a 3D graph for t and T against Y_B. I would like the interval t to be 0.2 to 30 and the interval of T to be 600 to 850. Here is my code below:
T=600:1:850;
t=0.2:0.1:30;
[tm,Tm] = meshgrid(t, T);
k1 = 10^7.*exp(-12700./Tm);
k2 = 5*10^4.*exp(-10800./Tm);
k3 = 7*10^7.*exp(-15000./Tm);
Y_B = (k1/(k1-k2-k3))*(exp(-(k1+k3)*tm)-exp(-k2*tm));
Y_Bmax = max(Y_B(:));
Idx = find(Y_B(:) == Y_Bmax);
[Y_BmaxRow,Y_BmaxCol] = ind2sub(size(Y_B), Idx);
figure(1)
mesh(t,T,Y_B)
view(40, 45)
grid on
The output error tells me that the inner matrix dimensions do not agree. However, I cannot see how to fix this.
0 Kommentare
Akzeptierte Antwort
Star Strider
am 1 Feb. 2018
You have to do element-wise operations, so replace / with ./, and * with .* in your ‘Y_B’ calculation:
Y_B = (k1./(k1-k2-k3)).*(exp(-(k1+k3).*tm)-exp(-k2.*tm));
This expression works.
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Discrete Data Plots finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!