Structure Assginment

I need a better approach to assign matrix to a structure. Currently I have

 A = 5 by 1 struct with Loc & Err variables, A(1:5).Loc & A(1:5).Err,
 I have Values matrix 5 by 6 where Loc info stored.

My code;

 for i=1:5
    A(i).Loc = Values(i,:)
 end

Is there easy way of assignment. I have a very complex structure, this is very simplified version of it. Any ideas??

[Daniel Shub]

This seems pretty easy to understand for me. What do you mean by easy?

Answer 1

[Walter Roberson]

Try this:

vcell = mat2cell(Values, ones(1, size(Values,1)), size(Values,2));
[A.Loc] = vcell{:};

[Umit]

It is close but not what I want, Lets say my values are 12 by 6 matrix, this one creates A.Loc 12 by 1, not A by 12 by 1 with each Loc 1 by 6. This is what I want. 'A(12).Loc(6)'

[Walter Roberson]

I had assumed here that you had already created A as a structure array. Otherwise,

[A(1:size(Values,1)).Loc] = vcell{:};

[Daniel Shub]

If there are lots of fields you might want to consider cell2struct

[Umit]

It works, thank you. This is what I want

Answer 2

[Jan]

There is no easy way to assign a very complicated structure.

Using a loop is most likely the easiest and most efficient method, especially if you use implicite pre-allocation by running the loop from the end to the start.