for loop with exceptions

I wanted to run the loop
for even = 2:2:26
but I don't want to include 4. how do i say this?

Antworten (2)

Pawel Jastrzebski
Pawel Jastrzebski am 8 Jan. 2018
Bearbeitet: Pawel Jastrzebski am 8 Jan. 2018

0 Stimmen

loopCounter = [2,6:2:26]
for i = loopCounter
i
% your code
end
Jan
Jan am 8 Jan. 2018

0 Stimmen

for even = 2:2:26
if even ~= 4
disp(even)
end
end
Or
index = 2:2:26;
index(index == 4) = [];
for k = index
disp(k);
end
Or for a larger list of excluded variables:
index = 2:2:26;
index = setdiff(index, [4,8,18]);
for k = index
disp(k);
end

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Gefragt:

cgo
am 8 Jan. 2018

Beantwortet:

Jan
am 8 Jan. 2018

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