Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
cell contents assignment to a non-cell array object
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
clc; clear all;
close all;
%disp('******************* LMI *******************')
%warning('off','YALMIP:strict')
global r
yalmip('clear');
r=2; c1=1; C=[c1 0 0 0 0 0; 0 c1 0 0 0 0; 0 0 c1 0 0 0; 0 0 0 c1 0 0; 0 0 0 0 c1 0; 0 0 0 0 0 c1];
A{1}=[-0.01 0 0;0 -.05 0;1 .01 0];
A{2}=[0 .01 -0.1;0 0 -1;0 .02 .1];
B{1}=[0;-.02;.01];
B{2}=[0;-.02;.01];
D{1}=[0.01;.002;.001];
D{2}=[-.01;.02;.04];
E{1}=[0 -2 0;2 0 0;1 -.2 0];
E{2}=[0 -1 1;.1 -1 0;1 -1 0];
C{1}=[0 .1 0];
C{2}=[1 0 .10];
K{1}=[.001 .3 0];
K{2}=[-2 -.03 1];
M{1}=0.01;
M{2}=1.5;
zer=[0 0 0;0 0 0;0 0 0];
zer1=[0;0;0];
L=[1 2 1];
%TildA{1}=[-B{1}*M{1}*C{1} zer; zer -B{1}*M{1}*C{1}];
% define known matrix
for i=1:r
for j=1:r
TilA{i,j}=[A{i} zer;
zer A{j}+B{j}*K{j}];TildA{j}=[-B{j}*M{j}*C{j} zer; zer -B{j}*M{j}*C{j}];
TilB{j}=[-B{j}*M{j} B{j}*M{j}*C{j}; zer1 zer];
TilD{i}=[D{i};zer1];
TilE{i}=[E{i}; zer];
end end
1 Kommentar
Walter Roberson
am 9 Jan. 2018
Bearbeitet: Walter Roberson
am 13 Apr. 2018
Using "clear all" inside a program is like Wile E. Coyote blowing up the butte he is standing on, expecting that he will be safe from falling as long as he does not look down. The only time you should ever use "clear all" inside a program is if you are writing a short script that you intend to be like restarting MATLAB without actually restarting MATLAB.
Antworten (1)
ANKUR KUMAR
am 9 Jan. 2018
C{1}=[0 .1 0];
C{2}=[1 0 .10]; K{1}=[.001 .3 0];
The errors are in these above codes. You already have defined C in double format (as in matrix in the third line). And you are trying to enter in C input as in cell. This is not possible.
My suggestion is to change the above code by
C1{1}=[0 .1 0];
C1{2}=[1 0 .10]; K{1}=[.001 .3 0];
Few more change you should to do are,
TildA{j}=[-B{j}*M{j}*C1{j} zer; zer -B{j}*M{j}*C1{j}];
TilB{j}=[-B{j}*M{j} B{j}*M{j}*C1{j}; zer1 zer];
0 Kommentare
Diese Frage ist geschlossen.
Siehe auch
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!