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Segment Coordinates of split screen

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Steven Moran
Steven Moran am 27 Dez. 2017
Kommentiert: Walter Roberson am 29 Dez. 2017
I split screen into segments for my classifier. I don't just want to classify each segment, I want the pixel coordinates of each segment as well. How do I do this?
thanks

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Walter Roberson
Walter Roberson am 27 Dez. 2017
Are the segments all the same size? If so then you should be able to easily convert segment index to screen coordinates.
coordinates_of_start = (index - 1) * width_in_this_direction + 1;
coordinates_of_end = index * width_in_this_direction;
  2 Kommentare
Steven Moran
Steven Moran am 29 Dez. 2017
What value is the 'index' ?
how is this different from regionprops function?
thanks
Walter Roberson
Walter Roberson am 29 Dez. 2017
index is the number of the segment in a particular direction. So the 3rd segment down, 4th over, would call for index numbers 3 for vertical direction and 4 for horizontal direction.

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Weitere Antworten (1)

Image Analyst
Image Analyst am 28 Dez. 2017
Bearbeitet: Image Analyst am 28 Dez. 2017
What do you mean by segmentation for your classifier? Is it like you want to segment the standard peppers.png demo image into purple region(s), red regions, green regions, and yellow regions, and you want the pixel coordinates of each segment (each class)? And you want to split up the screen to show masks for each segmentation (class)? If so, you can segment the image using whatever method you want, such as classify() function or the Color Thresholder app, then take the mask for each color class and use find() or regionprops() to get the (x,y) coordinates for each class.
  1 Kommentar
Steven Moran
Steven Moran am 28 Dez. 2017
The image is split into segments of equal size. Then each segment is classified in my deep learning algorithm. So the classification comes after the split occurs.
Each segment of pixels is classified, but I want each segment to also have its coordinates recorded because I'm coordinating that with mechanical stage movements.
Hope that makes sense. thanks for your answer

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