How to aggregate data on seasonal basis?

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Hydro
Hydro am 21 Dez. 2017
Hello, My seasons are defined as Dec-Feb, March-May, June-August, and Sep-Nov. My data is organized in Jan-December format with daily time step. the following code will re-arrange the data on a mean seasonal basis in the sequential order (e.g Q1= Jan - March, Q2=April - June), however, in North America season are different as I explained earlier. Can someone suggest a way forward or a code piece of code?
A=rand(730,2);
t1=(datetime(1981,1,1):datetime(1982,12,31))';
TT=timetable(t1,A);
TT2=retime(TT,'quarterly','mean');
Many thanks,
Ameer

Akzeptierte Antwort

Akira Agata
Akira Agata am 29 Jun. 2018
You can do that by setting new time vector as the 2nd input variable of retime function, like:
t2 = [datetime(1980,12,1):calmonths(3):datetime(1983,2,1)]';
TT2 = retime(TT,t2,'mean');
The result looks like:
>> TT2
TT2 =
9×1 timetable
t1 A
__________ __________________
1980/12/01 0.55223 0.4327
1981/03/01 0.46912 0.44696
1981/06/01 0.47352 0.46669
1981/09/01 0.51435 0.51787
1981/12/01 0.47761 0.52672
1982/03/01 0.51506 0.50781
1982/06/01 0.51125 0.58926
1982/09/01 0.491 0.52664
1982/12/01 0.84221 0.70557
  3 Kommentare
ugur uresin
ugur uresin am 3 Jul. 2018
+1
Aries Dwi Siswanto
Aries Dwi Siswanto am 26 Apr. 2020
Hi Andrei Bobrov and Ugur Uresin,
t2 = [datetime(1980,12,1):calmonths(3):datetime(1983,2,1)]';
TT2 = retime(TT,t2,'mean');
Which part will added by 1?
Thank you,

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