How to find pattern in an array?

86 Ansichten (letzte 30 Tage)
MathWorks Support Team
MathWorks Support Team am 5 Dez. 2017
Kommentiert: gwoo am 25 Mai 2022
How to find a pattern from a numeric array?
For example, there is a numeric array B and pattern (or mask) A. How to get the pattern location found in B? 
 
>> A = [1 2 3];
>> B = [5,4,3,1,2,3,5,4,1,2,3,4,5];
 
Expected output: 4, 9
 

Akzeptierte Antwort

MathWorks Support Team
MathWorks Support Team am 5 Dez. 2017
There is no built-in MATLAB function that performs the exact operation described.
However, you can use a single for-loop and the built-in "all" and "find" functions to create a custom function that will output the desired behavior:
>> function output = pattern(B, A)
>> SIZE = length(B) - length(A);
>> match = zeros(1, SIZE);
>> for i=1:SIZE
>> match(i) = all(B(i:i-1+length(A)) == A);
>> end
>> output = find(match == 1);
>> end
  1 Kommentar
gwoo
gwoo am 25 Mai 2022
As @claudio points out below in More Answers, strfind(B, A) does exactly what is requested.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

claudio
claudio am 14 Mai 2020
output = strfind(B,A);
  1 Kommentar
claudio
claudio am 14 Jan. 2021
No exceptions. if you have a particular request you can submit it to evaluate the specific case
str = sprintf('Special string for \t Karel \t K');
pattern = sprintf('\t');
idxTab = strfind(str,pattern)
idxTab =
20 28

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Multidimensional Arrays finden Sie in Help Center und File Exchange

Produkte


Version

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by