How to find a pattern from a numeric array?
For example, there is a numeric array B and pattern (or mask) A. How to get the pattern location found in B? 
 
>> A = [1 2 3];
>> B = [5,4,3,1,2,3,5,4,1,2,3,4,5];
 
Expected output: 4, 9
 

 Akzeptierte Antwort

MathWorks Support Team
MathWorks Support Team am 5 Dez. 2017

0 Stimmen

There is no built-in MATLAB function that performs the exact operation described.
However, you can use a single for-loop and the built-in "all" and "find" functions to create a custom function that will output the desired behavior:
>> function output = pattern(B, A)
>> SIZE = length(B) - length(A);
>> match = zeros(1, SIZE);
>> for i=1:SIZE
>> match(i) = all(B(i:i-1+length(A)) == A);
>> end
>> output = find(match == 1);
>> end

1 Kommentar

gwoo
gwoo am 25 Mai 2022
As @claudio points out below in More Answers, strfind(B, A) does exactly what is requested.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

claudio
claudio am 14 Mai 2020

2 Stimmen

output = strfind(B,A);

1 Kommentar

No exceptions. if you have a particular request you can submit it to evaluate the specific case
str = sprintf('Special string for \t Karel \t K');
pattern = sprintf('\t');
idxTab = strfind(str,pattern)
idxTab =
20 28

Melden Sie sich an, um zu kommentieren.

Kategorien

Produkte

Version

R2017b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by