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Matrix manipulation using reshape

1 Ansicht (letzte 30 Tage)
Prabha Kumaresan
Prabha Kumaresan am 18 Dez. 2017
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
If A=
1 0 0 0 0 0 0 0 0 0
0 2 0 0 0 0 0 0 0 0
0 0 3 0 0 0 0 0 0 0
0 0 0 4 0 0 0 0 0 0
0 0 0 0 5 0 0 0 0 0
0 0 0 0 0 6 0 0 0 0
0 0 0 0 0 0 7 0 0 0
0 0 0 0 0 0 0 8 0 0
0 0 0 0 0 0 0 0 9 0
0 0 0 0 0 0 0 0 0 10
I got B =
1 2 0 0 0 0 0 0 0 0
1 2 0 0 0 0 0 0 0 0
0 0 3 4 0 0 0 0 0 0
0 0 3 4 0 0 0 0 0 0
0 0 0 0 5 6 0 0 0 0
0 0 0 0 5 6 0 0 0 0
0 0 0 0 0 0 7 8 0 0
0 0 0 0 0 0 7 8 0 0
0 0 0 0 0 0 0 0 9 10
0 0 0 0 0 0 0 0 9 10
using
B = reshape(repmat(max(reshape(A,2,[])),2,1),size(A)).
But if i want to get C =
1 0 3 0 0 0 0 0 0 0
0 2 0 4 0 0 0 0 0 0
1 0 3 0 0 0 0 0 0 0
0 2 0 4 0 0 0 0 0 0
0 0 0 0 5 0 0 8 0 0
0 0 0 0 0 6 0 0 9 0
0 0 0 0 0 0 7 0 0 10
0 0 0 0 5 0 0 8 0 0
0 0 0 0 0 6 0 0 9 0
0 0 0 0 0 0 7 0 0 10
from A how the reshape can be written?
  2 Kommentare
Roger Stafford
Roger Stafford am 18 Dez. 2017
How would you generalize what is desired for an arbitrary size diagonal matrix? It is fairly easy to produce the desired result for your particular size.
Prabha Kumaresan
Prabha Kumaresan am 18 Dez. 2017
I need to have random grouping of rows which reults in sharing their values.

Antworten (1)

Roger Stafford
Roger Stafford am 18 Dez. 2017
If the "grouping" is to be randomly determined, do this:
n = size(A,1);
p = mod((0:n-1)+randi(n-1,1,n),n)+1; % p(k) never equals k
B = A;
for k = 1:n
B(p(k),k) = B(k,k);
end
If you have already determined a vector p to be used, then leave out the second line.
  1 Kommentar
Prabha Kumaresan
Prabha Kumaresan am 26 Dez. 2017
The following code executes but I am unable to get the random grouping of users.
N_UE=[10 20 30 40 50];
N_SC=[60 70 80 90 100];
for t= 1:length(N_UE)
for r = 1:length(N_SC)
C=rand(N_UE(t),N_SC(r));
s = size(C,1);
p = mod((0:s-1)+randi(s-1,1,s),s)+1; % p(k) never equals k
B = C;
for k = 1:s
B(p(k),k) = B(k,k);
end
end
end

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