Hi,
I have below two different times, and want to calculate time elapsed:
2017-12-13-T16:00:23.488+08:00
2017-12-13-T16:02:24.982+08:00
Many thanks in advance,

 Akzeptierte Antwort

Star Strider
Star Strider am 16 Dez. 2017
One approach:
v = {'2017-12-13-T16:00:23.488+08:00'
'2017-12-13-T16:02:24.982+08:00'};
T = datenum(v, 'yyyy-mm-dd-THH:MM:SS.FFF')
dT = etime(datevec(T(2)),datevec(T(1))) % Elapsed Time In Seconds
dT =
121.49
NOTE In theory, datetime can do something like this, however it will not import your data using the date format, and refuses to automatically recognise the time zone. I suppose datetime has its uses, but they frequently elude me. Anyway, the ‘classic’ functions work.

4 Kommentare

Sir,
I want to get the current time in the following format:
2017/12/16 10:46:18 I use: currentTime=clock datenum(currentTime) currentTime =
1.0e+03 *
2.0170 0.0120 0.0160 0.0110 0.0450 0.0382
The I convert:
datenum(currentTime)
ans =
7.3705e+05
But Can I print the time format using clock as: 2017/12/16 10:46:18?
Yes. Use the datestr (link) function:
t = clock;
ds = datestr(t, 'yyyy/mm/dd HH:MM:SS')
ds =
'2017/12/15 22:17:32'
Thanks Sir. It works.
As always, my pleasure.

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