Assigning values to an array using elements of another array after each element goes through a check

17 Ansichten (letzte 30 Tage)
Hello,
Let's say that i have an array (e.g zeros(5,5)).
I'd like to use each element my array has, put each element through an if statement check, make some calculations, and assign that new value to another array that has the same dimensions as my initial one.
If anybody has any idea i'd be of great help!
Thanks!:)

Akzeptierte Antwort

YT
YT am 14 Dez. 2017
Bearbeitet: YT am 14 Dez. 2017
I think your looking for something like this
start_matrix = rand(5,5); %rand 5x5, values between 0 and 1 (cause whats the point in comparing zeros)
end_matrix = zeros(size(start_matrix)); %same size as starting matrix
for i = 1:size(start_matrix,1)
for j = 1:size(start_matrix,2)
if (start_matrix(i,j) > 0.5)
end_matrix(i,j) = start_matrix(i,j) * 666; %some crazy calculations
else
end_matrix(i,j) = start_matrix(i,j); %no crazy calculations if <= 0.5
end
end
end
end_matrix

Weitere Antworten (1)

Matt J
Matt J am 14 Dez. 2017
Bearbeitet: Matt J am 14 Dez. 2017
I'd like to use each element my array has, put each element through an if statement check
Just be aware that that's normally the kind of thing you try to avoid in MATLAB. For instance, YT's example is much more efficiently implemented as follows for large matrices,
condition = start_matrix>0.5;
end_matrix=start_matrix;
end_matrix(condition)=start_matrix(condition)*666;
  2 Kommentare
YT
YT am 14 Dez. 2017
I agree to what you said, but I think it's useful for beginners to understand how looping through a matrix works.
Matt J
Matt J am 14 Dez. 2017
Bearbeitet: Matt J am 14 Dez. 2017
Yes, I know. I just want the OP to be aware of important alternatives.

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