Convert a single column in cell array to datetime format

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I have a cell array which I imported with textscan and the first column is a date/time stamp. I want to convert this date/time stamp to a true datetime.
The cell array (data_temp) looks like this:
"2017-01-15 13:50:46.500" "OPC.Temperature.BottomTemperature" "23"
"2017-01-15 13:50:50.203" "OPC.Temperature.BottomTemperature" "24"
"2017-01-15 13:52:06.937" "OPC.Temperature.BottomTemperature" "22"
"2017-01-15 13:52:22.578" "OPC.Temperature.BottomTemperature" "24"
I have tried:
% data_temp = datetime(data_temp(:,1),'InputFormat','yyyy-MM-dd HH:mm:ss.SSS');
This converts the whole cell array to datetime and deletes the 2nd and 3rd columns. Using
data_temp{:,1}
gives me these errors:
Error using datetime (line 510)
Invalid parameter name: 2017-01-15 13:50:50.203.
Error in parser (line 39)
data_temp = datetime(data_temp{:,1},'InputFormat','yyyy-MM-dd HH:mm:ss.SSS');
I am not sure what I am doing wrong. I am doing this so I can export the data to a sql database for archiving of a manufacturing process.
Edit:
This my full code so far
%parses .plg file from Log file
fileID = fopen('test.txt');
scan = textscan(fileID,'%s %s %s %s %s %s %s %s %s %s','collectoutput', true,'Delimiter','|');
fclose(fileID);
% combines textscan cell arrays to one cell array
scan = scan{:};
%determines number of paramater rows and counts all rows in textscan cell
%array
num_nonblank = sum(~strcmp(scan(:,10),''));
num_nonblank_plusone = num_nonblank + 1;
row_count = size(scan,1);
%makes 2 copies of the textscan cell array and convert to strings
parameters = scan;
parameters = string(parameters);
data = scan;
data = string(data);
%deletes extra columns and parameter rows from data cell array
data(:,(6:10)) = [];
data((1:num_nonblank),:) = [];
%deletes data rows from parameter cell array
parameters((num_nonblank_plusone:row_count),:) = [];
%create cell arrays for individual data types
data_temp = data;
%remove all rows not containing 'OPC.Temperature.BottomTemperature' in
%column 2
temp_string = 'OPC.Temperature.BottomTemperature';
temp_comp = data_temp(:,2) ~= temp_string;
data_temp(temp_comp,:) = [];
%remove extra information from columns 3 & 4 from data_temp
data_temp(:,(2:4)) = [];
  1 Kommentar
per isakson
per isakson am 10 Dez. 2017
Neither am I. This works here on R2016a
>> dt=datetime( '2017-01-15 13:50:50.203','InputFormat','yyyy-MM-dd HH:mm:ss.SSS')
dt =
2017-01-15 13:50:50
Comments:
  • Strange that you get an error for the second row, rather than the first
  • Have you looked for non-printing characters?

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Akzeptierte Antwort

Star Strider
Star Strider am 10 Dez. 2017
I would create a table from ‘data_temp’, then convert the first variable to a datetime array:
data_temp = {"2017-01-15 13:50:46.500" "OPC.Temperature.BottomTemperature" "23"
"2017-01-15 13:50:50.203" "OPC.Temperature.BottomTemperature" "24"
"2017-01-15 13:52:06.937" "OPC.Temperature.BottomTemperature" "22"
"2017-01-15 13:52:22.578" "OPC.Temperature.BottomTemperature" "24"};
data_table = cell2table(data_temp);
data_table.data_temp1 = datetime(data_table.data_temp1,'InputFormat','yyyy-MM-dd HH:mm:ss.SSS');
  10 Kommentare
Star Strider
Star Strider am 10 Dez. 2017
Try this:
data_temp = {'2017-01-15 13:50:46.500' 'OPC.Temperature.BottomTemperature' '23'
'2017-01-15 13:50:50.203' 'OPC.Temperature.BottomTemperature' '24'
'2017-01-15 13:52:06.937' 'OPC.Temperature.BottomTemperature' '22'
'2017-01-15 13:52:22.578' 'OPC.Temperature.BottomTemperature' '24'};
temp_string = 'OPC.Temperature.BottomTemperature';
temp_comp = ~cellfun(@strcmp, data_temp(:,2), repmat({temp_string},size(data_temp,1),1));
It runs, and appears to produce the correct result. I tested it on the cell array I created from the data you posted, that I assume to be similar to the original cell array (before the string call).
Douglas Anderson
Douglas Anderson am 4 Apr. 2022
Wow! Amazing! Cells are always a mystery to me. Thank you!!!

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