Function not returning full matrix

I have a matrix around 20,000 by 20 and when I use this codes it only returns 1000 by 20. I'm sure the problem has to be on the for loop I just don't know how to get this function to show me the whole matrix.

function ....
i=length(data_2);
for i=1:data_2
fprintf...
.....
end
end

[KSSV]

Don;t use length.......check with size. length gives you only maximum dimension......

[Stephen23]

Never use length in your code, because its output is not very useful. Use size or numel as required, but never use length.

[Jos (10584)]

These two lines are weird (and wrong)!

i=length(data_2);
for i=1:data_2_

I think you want something like

N = numel(data_2_)
for i=1:N

[Rafael]

numel fixed the problem. However, now I'm getting another problem since I changed

i=length(data_2) to N=numel(data_2)

The errors says, Index exceeds matrix dimensions.

Error in project (line6)
fprintf('%5.0f', data_2(i,1));

If I change the i to an N it says the same thing as if I leave it as an i.

[James Tursa]

Please show the current entire code snippet that is causing the problem.

[Rafael]

function [i]=table(data_2)
clc
fprintf('A B C D E F G H I J K L M N O P\n');
N=numel(data_2);
for i=N
fprintf('%1.0f',data_2(i,1));
fprintf('%1.0f',data_2(i,2));
fprintf('%1.0f',data_2(i,3));
fprintf('%1.0f',data_2(i,4));
fprintf('%1.0f',data_2(i,5));
fprintf('%1.0f',data_2(i,6));
fprintf('%1.0f',data_2(i,7));
fprintf('%1.0f',data_2(i,8));
fprintf('%1.0f',data_2(i,9));
fprintf('%1.0f',data_2(i,10));
fprintf('%1.0f',data_2(i,11));
fprintf('%1.0f',data_2(i,12));
fprintf('%1.0f',data_2(i,13));
fprintf('%1.0f',data_2(i,14));
fprintf('%1.0f',data_2(i,15));
fprintf('%1.0f',data_2(i,16));
fprintf('\n')
end
end

[James Tursa]

See the Answers below to fix your problem. E.g.,

N = size(data_2, 1);

[Rafael]

whos data_2 returns

Name     Size      Bytes    Class   Attributes
data_2   20,000x20  44k     double

[Rafael]

What do you mean in plain English. It's exactly what I said. I created a function that puts label on top of each columns. The problem is that it's not returning the whole matrix when I call it. It only returns 1000 by 20 matrix instead of the 20,000 by 20. So, when I use size(data_2,1) it only returns the last row of the matrix.

[Rafael]

I know it sounds confusing. If you'd see it you would understand what I am trying to do.

To make it clear. I have an array or matrix that has 20,000 rows and 20 columns. When I call the matrix which is called data_2 it returns the whole matrix like this,

Column 1 through 13
.................
Column 14 through 20
.................

I created a function which organize the matrix and puts label on top of each columns like this,

A B C D E F G...
1 2 3 4 5 6 7...
1 2 3 4 5 6 7...

So, the problem is that when I created this function and I called it returns only 1000 rows and 20 columns. It is not returning the whole matrix which is what I want.

function ....
i=length(data_2);
for i=1:data_2
fprintf...
.....
end
end

If I use,

i=size(data_2,1)
n=1:i

It only returns the last row from the matrix.

[Rafael]

If I run that it returns the whole matrix which is what I want. Now, it doesn't return the headers and it returns the matrix in the wrong order.

[Rafael]

Yes, I understand you were just giving me an example. I did have something inside that, but it is not returning on top of the columns. I copy you exact code for fprintf.

The order is from 10 13 7 up to row 20,000 for rows and columns is from 1 to 20. These codes returned it as 39 3 41 etc.

[Rafael]

The table is something like this, It goes from column 1 to 20 and row 1 to 20,000.

1  2  3  4  5  6 ... 20
10 13 17 43 76 42... 23
.
.
.
20,000

What I explained is that when I run the code you provided me, it returns those numbers in a different order like this,

1  2  3  4  5  6 ... 20
39 3  41 43 9  56... 1
.
.
.
18,390

Answer 1

[Rafael]

Okay, now when I do which cssm is working. It tells me where it is saved.

[Rafael]

That's where I am getting confused. What is data? I know cohl is the string. Is just telling me undefined function for data.

[Rafael]

The issue is when I tried to run your code,

colh = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T'};
data = permute( reshape( (1:120), 20,6 ), [2,1] );
fprintf( 1, [repmat( '%4s, '  , 1,20 ),'\n'], colh{:});
fprintf( 1, [repmat( '%4.0f, ', 1,20 ),'\n'], data );

This returns a 6 rows and 20 columns matrix with the strings on top. So, when I tried to run this,

cssm(data,colh)

It returns, Error using cssm Too many input arguments.

[Rafael]

function [colh]=cssm( data_2)
clc
colh = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P'};
    fprintf( [repmat( '%4s, ', 1,16 ),'\n'], colh{:} )
    N = size( data_2, 1 );
    for ii = 1 : N
        fprintf([repmat('%4.0f, ',1,16),'\n'], data_2(ii,:))
    end
end

[Rafael]

Okay, I changed it. Now when I run cssm(data,colh) it returns the matrix from column 1 to 20 and row 1 to 101. Organized.

[Rafael]

It returned the strings and the data which looks organized like in the original. However, it return it horizontally which doesn't fit in the command windows. It return and error.