Cannot open file , no permission

4 Ansichten (letzte 30 Tage)
Fareeha Yaseen
Fareeha Yaseen am 3 Dez. 2017
Beantwortet: Walter Roberson am 4 Dez. 2017
letters={'a'; 'b'; 'c'; 'd'; 'e'; 'f'; 'g'; 'h'; 'i'; 'j'; 'k'; 'l'; 'm'; 'n'; 'o' ;'p'; 'q'; 'r'; 's'; 't' ; 'u' ;'v' ;'w'; 'x' ;'y'; 'z'; 'aa'; 'bb'; 'cc'; 'dd'; 'ee'; 'ff'; 'gg'; 'hh'; 'ii'; 'jj'; 'kk'; 'll'; 'mm'; 'nn'; 'oo'; 'pp'; 'qq'; 'rr'; 'ss'; 'tt'; 'uu'; 'vv'; 'ww'; 'xx'; 'yy'; 'zz'; 'num0'; 'num1'; 'num2'; 'num3'; 'num4'; 'num5'; 'num6'; 'num7'; 'num8'; 'num9'};
increment =1;
for y = 1: 62
for k = 1 : 10
test = strcat(letters(y,:) , num2str(k));
imageName = imread('training_set',test,'.png');
imageName = rgb2gray(imageName);
x(:, increment) = (feature_extract(~im2bw(imageName)));
increment = increment + 1;
end;
end;
x = x';
Error using imread (line 347) Cannot open file "training_set" for reading. You might not have read permission.
Error in myFeatureScript (line 6) imageName = imread('training_set',test,'.png');
Please Help !!

Antworten (2)

chandrapal Singh
chandrapal Singh am 4 Dez. 2017
a=strcat('Your_Path\','Image.extenstion');
imageName =imread(a);

Walter Roberson
Walter Roberson am 4 Dez. 2017
imageName = imread(['training_set',test,'.png']);

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