Filter löschen
Filter löschen

How to EFFICIENTLY extract different length of vector from a different cell container?

1 Ansicht (letzte 30 Tage)
Dear all, the idea was to extract different length of vector from a different cell container as demonstrated at the code below. However, I wonder if we can achieve the same procedure using CELLFUN instead. I really appreciate for any tips.
Thanks in advance
Data_CELL = {randi(9, 10,1),randi(9, 6,1),randi(9, 12,1),randi(9, 12,1)};
Extracttill=[4 4 10 9]';
ExtractedData=cell(4,1);
for f_x=1:4
data=Data_CELL{1,:};
ExtrcFUntl=Extracttill(f_x,1);
ExtractedData{f_x,1}=data(1:ExtrcFUntl,:);
end
  2 Kommentare
balandong
balandong am 28 Nov. 2017
Thanks for the heads up. However, using CELLFUN make the overall code more compact, although I think it may consume the processing time.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Jos (10584)
Jos (10584) am 28 Nov. 2017
Bearbeitet: Jos (10584) am 28 Nov. 2017
Here is a "hidden-loop / one-liner":
Data_CELL = {randi(9, 10,1),randi(9, 6,1),randi(9, 12,1),randi(9, 12,1)};
Extracttill=[4 4 10 9]';
endExtractedData = arrayfun(@(k) Data_CELL{k}(1:Extracttill(k)),1:numel(Data_CELL),'un',0)
  2 Kommentare
balandong
balandong am 28 Nov. 2017
Hi Jos, Thanks for the quick reply and awesome solution. Really appreciate it.
Btw, what do you mean by Do you not want to extract the values from 1 until a specific value, rather than a single value?. Your solution above does answer my original question actually.
Jos (10584)
Jos (10584) am 28 Nov. 2017
Oh, sorry, I read your question to quickly ... answer updated!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by