how to find min or max value in each row of a matrix and its index, if a matrix is 3x2 it will find the min in first row

R= [27 25 21; 35 38 37; 42 47 49]; 1st min value will be 21

Answer 1

[Mischa Kim]

Use

 [val,loc] = min(R')
 val =
    21    35    42   % min value in each row
 loc =
     3     1     1   % column location of min value

[Bashir Yusuf Bichi]

thank you for you help, but how can I access 1 row at a time?

[Mischa Kim]

[val,loc] = min(R(1,:)) % min value in 1st row
val =
  21
loc =
   3

Replace the "1" in the min command by a running index to step through each row, e.g., using a loop.

[Bashir Yusuf Bichi]

thank you

[Fahim MUMAND]

suppose a matrix R = ones(4,4)

Every element is maximum and minimum, how to extract their indices?

How to extract the indices of max or min if there are more than 1 in col and in row?

Answer 2

[Ariunbolor Purvee]

absDiff=[1 2 3; 4 5 6; 7 8 9; 9 10 12];

MaxMinAveRow= MaxMinAveOfRow(absDiff);

display(MaxMinAveRow);

function MaxMinAveRow= MaxMinAveOfRow(absDiff)

n=length(absDiff);

maxRow=zeros(n,1);

minRow=zeros(n,1);

aveRow=zeros(n,1);

sum=0;

for i=1:n

maxRow(i)=sum+max(absDiff(i,:));% max of row

minRow(i)=sum+min(absDiff(i,:));% min of row

aveRow(i)=sum+mean(absDiff(i,:));% average of row

end

MaxMinAveRow=[ maxRow,minRow, aveRow ];

end

The result on Command Window

MaxMinAveRow =

3.0000 1.0000 2.0000

6.0000 4.0000 5.0000

9.0000 7.0000 8.0000

12.0000 9.0000 10.3333

[madhan ravi]

Using sum as a variable is not a good idea, sum() is an in-built function.