Please help with For Loop

4 Ansichten (letzte 30 Tage)
Raisul Islam
Raisul Islam am 6 Nov. 2017
Kommentiert: Raisul Islam am 7 Nov. 2017
u1 = v(:,1);
a2 = v(:,1)\v(:,2);
u2 = v(:,2) - v(:,1)*a2;
a3 = v(:,[1 2])\v(:,3);
u3 = v(:,3) - v(:,[1 2])*a3;
a4 = v(:,[1 2 3])\v(:,4);
u4 = v(:,4) - v(:,[1 2 3])*a4;
% Structural residuals and covariance
b02 = [ 1 0 0 0;
-a2(1) 1 0 0;
-a3(1) -a3(2) 1 0;
-a4(1) -a4(2) -a4(3) 1 ];
u = [u1 u2 u3 u4 ];
Please advise how can I estimate a , u and b with for loop...in case I have many more variables then just four.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 6 Nov. 2017
Index your variables instead of using fixed variable name. Use cell arrays.
a{K} = v(:,K-1)\v(:,K);
u{K} = v(:,K) - v(:,K-1)*a{K};
  6 Kommentare
Walter Roberson
Walter Roberson am 6 Nov. 2017
Correction:
ncol = size(v,2);
u(:,1) = v(:,1);
a = zeros(ncol, ncol);
for K = 2 : size(v,2)
a(1:K-1,K) = v(:,1:K-1)\v(:,K);
u(:,K) = v(:,K) - v(:,1:K-1)*a(1:K-1,K);
end
b = diag(ones(1,ncol)) - tril(a.');
Raisul Islam
Raisul Islam am 7 Nov. 2017
thank you so much

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by