eval() returns NaN when my matrix gets really big.

7 Ansichten (letzte 30 Tage)
Mads
Mads am 25 Apr. 2012
Kommentiert: Adilet Nuratay am 31 Jan. 2021
Hi
Im making a model of a mass-spring system where I can increase the numbers of masses. I use modal analysis where I transform my eq's into the Q domain and then back again.
My final result is a [n,1] vector where n is the numbers of masses.
When I use:
n = 4 % Number os masses %
T = 1 % Time which is set as "syms T" %
eval(X) % X is my [n,1] vector %
my result is something like:
ans =
0.0158
0.0739
0.1778
0.8150
but when I pick n to be more then 4 i just get "NaN" and I think it is because my vector gets too big for eval()..
When I look at my X vector it looks like this:
(227072026347336273211456024361092029598452603947709420093308928000*sin(T))/3496036292367407553353910200384804229923697463840499539488117510161+..... and it continues likes this for 2 full pages.
What to do?
Thank you!

Akzeptierte Antwort

Alexander
Alexander am 25 Apr. 2012
Please try the following:
double(vpa(evalin(symengine, ['subs(' char(X) ', T=' num2str(T) ')'])))
This does the following steps:
  1. Substitute the sym T inside the symbolic engine.
  2. Evaluate the result using variable-precision arithmetic.
  3. Convert the result to double.
  2 Kommentare
Walter Roberson
Walter Roberson am 25 Apr. 2012
I think you should probably be able to simplify that to
double(subs(X))
Adilet Nuratay
Adilet Nuratay am 31 Jan. 2021
Sorry, I have similar problem.
But I cannot understand the given command. Can anyone clarify it ?
Thank you in advance!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Mads
Mads am 25 Apr. 2012
Thanks you two!! Both suggestions worked but Alexanders was for some reason like 20times faster
  4 Kommentare
Walter Roberson
Walter Roberson am 25 Apr. 2012
If T is a vector then you would need 'T=[' num2str(T) ']'
Alexander
Alexander am 25 Apr. 2012
Yeah, you are right. My suggestion does not work for vectors, I did not think about that.

Melden Sie sich an, um zu kommentieren.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by