Using an if/else statement inside of a for loop

Hi! I am trying to write an if else statement inside of a for loop in order to determine how many people surveyed had a specific response. I posted my code below. Every time I run it instead of generating the numbers, it generates my fprintf statement that amount of time. I am just really confused because I followed the template my professor gave and it just isn't working for me. Thank you,
y=load('Class19_survey.txt');
ag=0;
ne=0;
dis=0;
for k=1:length(y)
if y(k)>=4
ag=ag+1;
fprintf('\nThe number of people who agree is\n',ag)
elseif y(k)==3
ne=ne+1
fprintf('\nThe number of neutral responses is\n',ne)
else y(k)<=2
dis=dis+1
fprintf('\nThe number of disagree responses is\n', dis)
end
end

1 Kommentar

Sorry here is an easier version to read
y=load('Class19_survey.txt');
ag=0;
ne=0;
dis=0;
for k=1:length(y)
if y(k)>=4
ag=ag+1;
fprintf('\nThe number of people who agree is\n',ag)
elseif y(k)==3
ne=ne+1
fprintf('\nThe number of neutral responses is\n',ne)
else y(k)<=2
dis=dis+1
fprintf('\nThe number of disagree responses is\n', dis)
end
end

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 Akzeptierte Antwort

KL
KL am 1 Nov. 2017

0 Stimmen

Perhaps you want something like this,
y=load('Class19_survey.txt');
ag=0;
ne=0;
dis=0;
for k=1:length(y)
if y(k)>=4
ag=ag+1;
elseif y(k)==3
ne=ne+1;
else y(k)<=2
dis=dis+1;
end
end
fprintf('\nThe number of people who agree is\n',ag)
fprintf('\nThe number of neutral responses is\n',ne)
fprintf('\nThe number of disagree responses is\n', dis)
but you could also do it without the loop and if statements,
ag = length(y(y>=4));
ne = length(y(y==3));
dis = length(y(y<=2));

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 1 Nov. 2017

0 Stimmen

y=load('Class19_survey.txt');
ag=0;
ne=0;
dis=0;
for k=1:length(y)
if y(k)>=4
ag=ag+1;
elseif y(k)==3
ne=ne+1;
else y(k)<=2
dis=dis+1;
end
end
fprintf('\nThe number of people who agree is\n',ag);
fprintf('\nThe number of neutral responses is\n',ne);
fprintf('\nThe number of disagree responses is\n', dis);

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