An Edge-Guided Image Interpolation Algorithm via Directional Filtering and Data Fusion

    function A=esintp(I)
  %%%%%process A%%%%%%%%%%%%%%%%%%%%%%%%%%%%
  [n,m]=size(I);
  n=2*n;m=2*m;
  A=zeros(n,m);

A(1:2:n,1:2:m)=I;
Ax=A;Ay=A;
f=[-1/16 9/16 9/16 -1/16];
for i=4:2:n-4
   for j=4:2:m-4
      x=[A(i-3,j-3) A(i-1,j-1) A(i+1,j+1) A(i+3,j+3)];
      y=[A(i+3,j-3) A(i+1,j-1) A(i-1,j+1) A(i-3,j+3)];
      Ax(i,j)=sum(x.*f);
      Ay(i,j)=sum(f.*y);
   end
end

for i=4:2:n-4
   for j=4:2:m-4
      zx=[Ax(i-2,j-2) Ax(i-1,j-1) Ax(i,j) Ax(i+1,j+1) Ax(i+2,j+2)];
      zy=[Ay(i+2,j-2) Ay(i+1,j-1) Ay(i,j) Ay(i-1,j+1) Ay(i-2,j+2)];

        x=[A(i-1,j-1) A(i+1,j+1) A(i+1,j-1) A(i-1,j+1)];
        mx=mean(x);

        px=sum((x-mx).^2)/3+0.1;
        pzx=sum((zx-mx).^2)/4+0.1;
        pzy=sum((zy-mx).^2)/4+0.1;

        pv1=pzx-px;pv1=max(0.01,pv1);
        pv2=pzy-px;pv2=max(0.01,pv2);

        R=[pv1 0;0 pv2];
        y=[Ax(i,j) Ay(i,j)]';
        H=[1;1];
        A(i,j)=mx+px*H'*(H*px*H'+R)^(-1)*(y-H*mx);
    end
  end

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
   Ax=A;Ay=A;
   f=[-1/16 0 9/16 1 9/16 0 -1/16];

     Ax=conv2(Ax,f);
     Ax=Ax(:,4:m+3);
     Ay=conv2(Ay,f');
     Ay=Ay(4:n+3,:);
     c=1.5;
     h=[-1 5 5 -1];h=h/sum(h);
  for i=5:2:n-5
     for j=4:2:m-4
        y=[Ax(i-2,j) A(i-1,j) A(i+1,j) Ax(i+2,j)];
        my=sum(h.*y);
        x=[Ax(i,j-2) Ax(i,j-1) Ax(i,j) Ax(i,j+1) Ax(i,j+2)];
        vx=cov(x)+0.1;
        vy=c*cov([y my])+0.1;
        A(i,j)=(Ax(i,j)*vy+my*vx)/(vx+vy);
     end
  end
  for i=4:2:n-4
     for j=5:2:m-5
        x=[Ay(i,j-2) A(i,j-1) A(i,j+1) Ay(i,j+2)];
        mx=sum(h.*x);
        y=[Ay(i-2,j) Ay(i-1,j) Ay(i,j) Ay(i+1,j) Ay(i+2,j)];
        vx=c*cov([x mx])+0.1;
        vy=cov(y)+0.1;
        A(i,j)=(mx*vy+Ay(i,j)*vx)/(vx+vy);
     end
  end

return;

can anyone explain this code???

[Royi Avital]

Could you point exactly what do you don't understand?

[qing zhao]

 this code have something wrong,haven't you found it?

Answer 1

[Image Analyst]

I bet the author could, but probably doesn't want to, or else he or she would have done so by adding comments. I'm not even going to attempt it.

Answer 2

[qing zhao]

Can someone provide some suggestions about above code.