I have written this function for the sine wave that takes different values of frequency(f0)and sampling frequency(fs) Can anyone help where I am doing wrong.
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function y= sin_f(length,amplitude,Frequency,phaseShift)
N=length;
f0 =Frequency;
phi= phaseShift;
A=amplitude;
y=zeros(1,N+1);
for n=1:N+1
y(n)=A*sin(2* pi* f0 * (n-1)+ phi);
end
N=40; % Number of samples
A=1.5; % Amplitude
k=1; % for subplot
phi =pi/2; % for phase angle
fs = 44000
x=[0:1:N];
m = [0, 0.05, 0.1,0.4,0.45,0.5,0.55,0.6]
%m=[0 .1 .2 .8 .9 1 1.1 1.2];
r=floor(length(m)/2);
for i= m
f0=m
y= sin_f(N,A,f0,phi);
figure(1)
subplot(r+1,2,k);
stem(x,y);
xlabel('Time Index n');
ylabel('Amplititude');
title(m(k));
k=k+1;
end
Antworten (1)
Walter Roberson
am 29 Okt. 2017
0 Stimmen
You tried to use length as the name of a parameter and also as the function that it more commonly represents.
Your code has no comments about what sizes are expected for the parameters, and does no checking; your code just crashes for no good reason if the user passes something non-scalar.
7 Kommentare
Aash
am 29 Okt. 2017
Aash
am 29 Okt. 2017
Walter Roberson
am 29 Okt. 2017
My previous response still applies.
Aash
am 29 Okt. 2017
Walter Roberson
am 29 Okt. 2017
Please think about this code:
ABC = [1 4 1 4 2 1 3 5];
disp('length(ABC) is')
length(ABC)
disp('ABC([2 3 4]) is')
ABC([2 3 4])
length = [3 1 4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3];
disp('length(ABC) is')
length(ABC)
Why did length(ABC) change?
Aash
am 29 Okt. 2017
Walter Roberson
am 29 Okt. 2017
N is not the problem. The problem is "length". You should avoid using variable names that are the same as MATLAB functions, because you will tend to forget that they are variables at the time you need the function.
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