Hi, I try to solve below question but I have a problem, my answer is wrong
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Write a function that is called like this: amag = accelerate(F1,F2,m). F1 and F2 are three-element column vectors that represent two forces applied to a single object. The argument m equals the mass of the object in units of kilograms. The three elements of each force equal the x, y, and z components of the force in Newtons. The output variable amag is a scalar that is equal to the magnitude of the object’s acceleration. The function calculates the object’s acceleration vector a by using Newton’s law: F = ma, where F is the sum of F1 and F2. Then it returns the magnitude of a. Hint: we are talking about physical vectors here, so the Pythagorean theorem will come in handy.
My answer is;
function amag = accelerate(F1,F2,m)
F = F1 + F2;
amag = F./m;
1 Kommentar
Walter Roberson
am 27 Apr. 2018
Please do not close questions that have an answer.
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Isaac DeVaughn
am 6 Dez. 2017
0 Stimmen
I think i understand the your answer basically there's an extra formula for the magnitude of F=squareroot(Fx^2+Fy^2+Fz^2) that is supposed to be implied by that last line. I didn't understand that from the question but thats kinda how magnitude works
1 Kommentar
Vaibhav Sharma
am 28 Jan. 2018
i understand this one a little bit but not fully pls do explain
Amit Kumar
am 19 Feb. 2018
0 Stimmen
what is wrong with code? this code runs correctly for some values but showing error for F1=[1;0;0], F2=[0;1;0] and m=1 function [ amag ] = accelerate( F1,F2,m ) F=(sqrt(F1.^2)+sqrt(F2.^2)); amag=sum(F/m); end
Muniba Arshad
am 9 Jul. 2018
Bearbeitet: Walter Roberson
am 9 Jul. 2018
Guys this is the correct solution,
amag = accelerate(F1,F2,m)
F_sum = F1 + F2;
F = sqrt(F_sum(1,1)^2+F_sum(2,1)^2+F_sum(3,1)^2);
amag = F/m;
Explanation: First add the vectors then find the magnitude of resultant vector and apply the formula a=F/m on it.
2 Kommentare
Naitikkumar Darji
am 19 Nov. 2018
can u explain how its work??
Walter Roberson
am 19 Nov. 2018
? The line at the bottom already explains it.
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