How to match initial index?
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I am very close to getting the index in Python to match with Matlab.
Here is the output of Python...
0.06 0.058125 0.05625 0.054375 0.0525 0.050625 0.04875 0.046875 0.045 0.043125 0.04125 0.039375 0.0375 0.035625 0.03375 0.031875 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Here is some of the Matlab code...
% clears variables and windows
clc, clear all
% user defined variables
AoA = 10*pi/180;
Uinf = 8.8;
rho = 1.204;
chord = 0.12;
span = chord*2;
thickness = 0.006;
minRad = thickness/2;
majRad = chord/4;
numPanels = 128;
xp = zeros(numPanels, 1)
yp = zeros(numPanels, 1)
% panel coordinates for a finite thickness plate with elliptical leading % edge (nodes)
xStep = chord/(numPanels/2);
xp = chord/2; % 0.06
yp = 0;
k = 1;
while k < numPanels/8
xp(k) = chord/2 - xStep*k
yp(k) = -minRad/majRad*(majRad^2-(majRad-xStep*k)^2)^(1/2)
k = k + 1;
end
Matlab output...
xp'
ans =
0.0581
0.0562
0.0544
0.0525
0.0506
0.0488
0.0469
0.0450
0.0431
0.0412
0.0394
0.0375
0.0356
0.0338
In Python the first value is 0.06, the value in Matlab is 0.058125. I need to hold numPanels = 128, don't want to change this to match indexing. In my Matlab code before the first while loop I have xp = chord/2 which is the 0.06, while yp = 0. When placing these outside the while loop will Matlab account those as the initial value at index 1?
Akzeptierte Antwort
Weitere Antworten (1)
No it is not going to happen, after inside the while loop, the xp and yp variables will be overridden by newly defined xp and yp vectors.
1 Kommentar
Zach Dunagan
am 20 Okt. 2017
Kategorien
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