Convert a vector into a structure array field

x= [2; 8; 6; 3; 7; 8]; 
for i=1:numel(x)
    s(i).x=x(i);
end

Do the same, but without cycle.

Answer 1

[Ray]

If struct s does not exist yet, you could use:

s = struct('x', num2cell(x));

[bbb_bbb]

Thank you. And if it does exist and I want to add a field x?

[Walter Roberson]

if x is the same length as the number of entries in the struct array s, then

temp = num2cell(x);
[s.x] = temp{:};

[bbb_bbb]

Thanks!