Calculating exact roots of 6th degree polynomial

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Deepayan Bhadra
Deepayan Bhadra am 18 Okt. 2017
Bearbeitet: Walter Roberson am 19 Okt. 2017
I've a fat 6x6 matrix E with symbolic variables. I'm trying to compute sqrt(eig(E'E)), ie, the singular values. The answer begins with 'root( ) etc. How do I get MATLAB to solve this 6th degree polynomial and show me more pleasing answers? Thanks a lot.

Antworten (1)

Image Analyst
Image Analyst am 19 Okt. 2017
Use roots(), not root().
  3 Kommentare
Walter Roberson
Walter Roberson am 19 Okt. 2017
root() is the placeholder that replaced RootOf() a couple of releases ago in the Symbolic Toolbox.
Walter Roberson
Walter Roberson am 19 Okt. 2017
Bearbeitet: Walter Roberson am 19 Okt. 2017
Which Galois group does it belong to? Because it is not generally possible to solve for exact algebraic roots.
By the way, have you ever looked at how long the roots are just for quartics? About 12500 characters per solution when using bare symbols for the coefficients; much much longer if the coefficients are expressions as you imply is happening for you.
Suppose you managed to find a (say) million character closed form for one of your eigenvalues: realistically, what would you do with it?

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