Filter löschen
Filter löschen

What is wrong in this code??

1 Ansicht (letzte 30 Tage)
theintern
theintern am 17 Okt. 2017
Kommentiert: theintern am 18 Okt. 2017
Could you please help me to solve the problem? Loop cannot stop.
Attached you can find the file. The function is digdata and the other is code. Thank you.

Akzeptierte Antwort

Jan
Jan am 17 Okt. 2017
In this loop:
while abs(res1)>0.01
As = vq.*(Us(j).^2)./(16.*(pi.^2).*msksi.*fs1(j));
res1 = As1(i)-As;
end
you calculate the same value in each iteration. As will never change its value. Therefore this must be an infinite loop.
Due to the missing comments, the purpose of this loop cannot be guessed. Therefore a reliable suggestion of improvement cannot be given.
  1 Kommentar
theintern
theintern am 17 Okt. 2017
Sorry, I am kind of new in Matlab. I am trying to apply attached step. Equation is the As formula that I wrote.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

theintern
theintern am 18 Okt. 2017
I changed this code with attached code, but I think the problem is in digdata function. I would like to find vq values which correspond (As(i), Vs). There is a dimensional problem that I couldn't solve.
  2 Kommentare
Jan
Jan am 18 Okt. 2017
Bearbeitet: Jan am 18 Okt. 2017
Please post details belonging to the question by editing the question, not as answers. Thanks.
"There is a dimensional problem that I couldn't solve." Then please post any details. Do you get an error message? Then post it completely.
The clear all in your code destroys the current work, if somebody tries to your code to help you. It is much smarter to store the code in a function instead of clearing everything brutally.
Your code will be much easier to read, if you select it an press Ctrl-I in the editor.
theintern
theintern am 18 Okt. 2017
Thank you, I will be more careful then. I solved the problem.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by