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Is there a better function to minimize than fminsearch ?

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abc abc
abc abc am 12 Okt. 2017
Bearbeitet: Birdman am 20 Okt. 2017
Hello, I would like to know if it exits a better function to minimize a function than fminsearch ? I have this line :
[X, fval, exitflag, output] = fminsearch(@func, X0, options, params)
I precise I have the optimization toolbox. Thank you for your help !
  1 Kommentar
Walter Roberson
Walter Roberson am 18 Okt. 2017
Do you need a global optimization or a local optimization? Is the function differentiable? Is its Jacobian known? Is its Hessian known? If you were to pass symbolic variables into the function would it be able to return a symbolic formula in response ?

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Antworten (2)

Birdman
Birdman am 18 Okt. 2017
There is a user-written function which contains Hooke-Jeeves algorithm. Maybe this will help you. The inputs and the outputs are clearly defined.
function [X,BestF,Iters] = hookejeeves(N, X, StepSize, MinStepSize, Eps_Fx, MaxIter, myFx)
% Function HOOKEJEEVS performs multivariate optimization using the
% Hooke-Jeeves search method.
%
% Input
%
% N - number of variables
% X - array of initial guesses
% StepSize - array of search step sizes
% MinStepSize - array of minimum step sizes
% Eps_Fx - tolerance for difference in successive function values
% MaxIter - maximum number of iterations
% myFx - name of the optimized function
%
% Output
%
% X - array of optimized variables
% BestF - function value at optimum
% Iters - number of iterations
%
Xnew = X;
BestF = feval(myFx, Xnew, N);
LastBestF = 100 * BestF + 100;
bGoOn = true;
Iters = 0;
while bGoOn
Iters = Iters + 1;
if Iters > MaxIter
break;
end
X = Xnew;
for i=1:N
bMoved(i) = 0;
bGoOn2 = true;
while bGoOn2
xx = Xnew(i);
Xnew(i) = xx + StepSize(i);
F = feval(myFx, Xnew, N);
if F < BestF
BestF = F;
bMoved(i) = 1;
else
Xnew(i) = xx - StepSize(i);
F = feval(myFx, Xnew, N);
if F < BestF
BestF = F;
bMoved(i) = 1;
else
Xnew(i) = xx;
bGoOn2 = false;
end
end
end
end
bMadeAnyMove = sum(bMoved);
if bMadeAnyMove > 0
DeltaX = Xnew - X;
lambda = 0.5;
lambda = linsearch(X, N, lambda, DeltaX, myFx);
Xnew = X + lambda * DeltaX;
end
BestF = feval(myFx, Xnew, N);
% reduce the step size for the dimensions that had no moves
for i=1:N
if bMoved(i) == 0
StepSize(i) = StepSize(i) / 2;
end
end
if abs(BestF - LastBestF) < Eps_Fx
break
end
LastBest = BestF;
bStop = true;
for i=1:N
if StepSize(i) >= MinStepSize(i)
bStop = false;
end
end
bGoOn = ~bStop;
end
function y = myFxEx(N, X, DeltaX, lambda, myFx)
X = X + lambda * DeltaX;
y = feval(myFx, X, N);
% end
function lambda = linsearch(X, N, lambda, D, myFx)
MaxIt = 100;
Toler = 0.000001;
iter = 0;
bGoOn = true;
while bGoOn
iter = iter + 1;
if iter > MaxIt
lambda = 0;
break
end
h = 0.01 * (1 + abs(lambda));
f0 = myFxEx(N, X, D, lambda, myFx);
fp = myFxEx(N, X, D, lambda+h, myFx);
fm = myFxEx(N, X, D, lambda-h, myFx);
deriv1 = (fp - fm) / 2 / h;
deriv2 = (fp - 2 * f0 + fm) / h ^ 2;
diff = deriv1 / deriv2;
lambda = lambda - diff;
if abs(diff) < Toler
bGoOn = false;
end
end
% end
  17 Kommentare
Birdman
Birdman am 20 Okt. 2017
I will deal with code and respond to you later.
Birdman
Birdman am 20 Okt. 2017
Bearbeitet: Birdman am 20 Okt. 2017
 Firstly, enter the following informations for the *hookejeeves* function.
N=..;
X=[a1 .. a11];
StepSize=[0.5 .. 0.5];
MinStepSize=[0.01 .. 0.01];
Eps_Fx=[];%let it be empty

Then, save the following function with the name hookejeeves

function [X,BestF,Iters] = hookejeeves(N, X, StepSize, MinStepSize, MaxIter, myFx)
%Başlangıç atamalarının yapılması. BestF=x(k+1), LastBestF=x(k) gibi
%düşünülebilir.
Xnew = X;
BestF = feval(myFx, Xnew, N);
LastBestF = 100 * BestF + 100;
%bGoOn değişkenine bağlı while döngüsü, maksimum iterasyon sayısına veya
%verilen toleransa ulaşılınca biter.
bGoOn = true;
Iters = 0;
%Civar aramasının gerçekleştiği while döngüsüdür.
while bGoOn
    Iters = Iters + 1;
    if Iters > MaxIter
      break;
    end
    X = Xnew;
  %N=2 değişken için arama yapılmaktadır.
    for i=1:N
      bMoved(i) = 0;
      bGoOn2 = true;
      while bGoOn2
        xx = Xnew(i);
        Xnew(i) = xx + StepSize(i);
        F = feval(myFx, Xnew, N);
        if F < BestF
          BestF = F;
          bMoved(i) = 1;
        else
          Xnew(i) = xx - StepSize(i);
          F = feval(myFx, Xnew, N);
          if F < BestF
            BestF = F;
            bMoved(i) = 1;
          else
            Xnew(i) = xx;
            bGoOn2 = false;
          end
        end
      end
    end
    for i=1:N
    bMadeAnyMove(i) = sum(bMoved(i));%Civar araması başarılıysa, bMadeAnyMove(i) değişkeni 0'dan farklı olur.
    if bMadeAnyMove(i) > 0
      Xnew1(i) = 2*Xnew(i) - X(i);%if bloğunda yeni x(k+1) değeri yukarıda kullanılmak üzere elde edilir.
    end
    end
    BestF = feval(myFx, Xnew1, N);
    LastBestF = feval(myFx, Xnew, N);
    %Fonksiyonun değeri bir öncekinden daha küçükse, bir önceki değerlerin
    %yeni x değerini bulurken kullanılması.
    for i=1:N
    if BestF < LastBestF 
        Xnew(i)=Xnew1(i);
        X(i)=Xnew(i);
      Xnew1(i) = 2*Xnew(i) - X(i);
    end
    end
    %Civar araması başarısızsa, adım sayısı yarıya düşürülür.
  for i=1:N
      if bMoved(i) == 0
        StepSize(i) = StepSize(i) / 2;
      end
    end
    %Adım sayısı, verilen adım sayısından daha küçük olursa iterasyon sonlanır.
    bStop = true;
    for i=1:N
      if StepSize(i) >= MinStepSize(i)
        bStop = false;
      end
    end
    bGoOn = ~bStop;
  end

Don't worry about the comment lines, they are in turkish. Then enter the following code:

hookejeeves(N,X,StepSize,MinStepSize,Eps_Fx,@intrafunc)

This one should work. Let me know the outcome. If you give 11 variables, it might take a little longer to calculate but do not worry and wait for it to get it done.

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Alan Weiss
Alan Weiss am 18 Okt. 2017
You might be interested in the Optimization Decision Table, which exists to help you choose the most appropriate solver.
Alan Weiss
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