Solving coupled Differential equations
    4 Ansichten (letzte 30 Tage)
  
       Ältere Kommentare anzeigen
    
I tried to solve following diff. eq. using 'dsolve' but (maybe) it's impossible.
So please help me how to solve following eq.s using matlab!!!!!
syms s1 s2 s3 g1 g2 g3 p1 p2 p3 t
h = 1; b = 2; e = exp(1); v = 1;
diffqp1 = 'Dp1 = h*b*s1*(g1-p3)-(e/v)*p1'
diffqp2 = 'Dp2 = h*b*s1*(g1-p3)-(e/v)*p2'
diffqp3 = 'Dp3 = h*b*s1*(g1-p3)-(e/v)*p3'
diffqs1 = 'Ds1 = -h*b*s1*(g1-p3)-(e/v)*s1'
diffqs2 = 'Ds2 = -h*b*s1*(g1-p3)-(e/v)*s2'
diffqs3 = 'Ds3 = -h*b*s1*(g1-p3)-(e/v)*s3'
3 Kommentare
  Walter Roberson
      
      
 am 11 Okt. 2017
				- Are your g1 g2 g3 functions or constants?
 - What boundary conditions are there?
 - you never use g2 or g3 but use g1 repeatedly
 
Presuming that g1 is a constant and not a function, then current syntax would look like
syms s1(t) s2(t) s3(t) g1 g2 g3 p1(t) p2(t) p3(t)
h = 1; b = 2; e = exp(1); v = 1;
Dp1 = diff(p1); Dp2 = diff(p2); Dp3 = diff(p3);
Ds1 = diff(s1); Ds2 = diff(s2); Ds3 = diff(s3);
diffqp1 = Dp1 == h*b*s1*(g1-p3)-(e/v)*p1;
diffqp2 = Dp2 == h*b*s1*(g1-p3)-(e/v)*p2;
diffqp3 = Dp3 == h*b*s1*(g1-p3)-(e/v)*p3;
diffqs1 = Ds1 == -h*b*s1*(g1-p3)-(e/v)*s1;
diffqs2 = Ds2 == -h*b*s1*(g1-p3)-(e/v)*s2;
diffqs3 = Ds3 == -h*b*s1*(g1-p3)-(e/v)*s3;
eqns = [diffqp1, diffqp2, diffqp3, diffqs1, diffqs2, diffqs3];
sol = dsolve(eqns);
Antworten (0)
Siehe auch
Kategorien
				Mehr zu 미적분 finden Sie in Help Center und File Exchange
			
	Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!