What does the error `Error in checkArgsF​orHandleTo​Print` mean?

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Brando Miranda
Brando Miranda am 8 Okt. 2017
Kommentiert: Rami A am 7 Apr. 2023
What does the error:
Error using checkArgsForHandleToPrint
Handle input argument contains nonhandle values.
Error in checkArgsForHandleToPrint
Error in print>LocalCreatePrintJob (line 97)
handles = checkArgsForHandleToPrint(0, varargin{:});
Error in print (line 38)
[pj, inputargs] = LocalCreatePrintJob(varargin{:});
if possible, how does one fix it too would be nice.
  3 Kommentare
Kalyan
Kalyan am 25 Jan. 2023
A=[1,2,3,4,5,6,7,7,7];
c=unique(A)
print(A);
same error
Error using checkArgsForHandleToPrint
Handle input argument contains nonhandle values.
Error in checkArgsForHandleToPrint
Error in print>LocalCreatePrintJob (line 97)
handles = checkArgsForHandleToPrint(0, varargin{:});
Error in print (line 38)
[pj, inputargs] = LocalCreatePrintJob(varargin{:});
Rami A
Rami A am 7 Apr. 2023
Hi Kalyan, I think you meant to use disp(A); instead of print(A);.

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Antworten (2)

Nathan Daubenmier
Nathan Daubenmier am 22 Jan. 2021
Try using :
fprintf('Info you are trying to print: %f', data_name);
rather than:
print('Info you are trying to print: %f', data_name);
Hope this helps!

mengqiu ren
mengqiu ren am 28 Sep. 2018
I have the same question.Have you solved it?

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