i have a string pattern as below of length 24
str1 = 'AAAAAABBBBBBCCCCCCDDDDDD'
now i want to create a new pattern from the str1 with the length i give,
if i give length of new pattern as 72 answer should be
str2 = 'AAAAAABBBBBBCCCCCCDDDDDDAAAAAABBBBBBCCCCCCDDDDDDAAAAAABBBBBBCCCCCCDDDDDD'
that is it should repeat pattern in str1 upto the limit i want
if i give 84 answer should be
str3 = 'AAAAAABBBBBBCCCCCCDDDDDDAAAAAABBBBBBCCCCCCDDDDDDAAAAAABBBBBBCCCCCCDDDDDDAAAAAABBBBBB'

1 Kommentar

darshana alaiya
darshana alaiya am 2 Apr. 2023
I want matrix with repeated pattern in 1st 3rd and 5th row.
for eg. 1 18 25 0 0 0 0 0 0
3 23 27 0 0 0 0 0 0
0 0 0 5 28 29 0 0 0
0 0 0 7 33 31 0 0 0
so on...

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 Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 4 Okt. 2017
Bearbeitet: Andrei Bobrov am 4 Okt. 2017

1 Stimme

m = 84;
[s,~,c] = unique(str1,'stable');
n = numel(c);
out = s(c(rem(0:m-1,n)+1));
or
m = 84;
k = repmat(str1,1,ceil(m/numel(str1)));
out = k(1:m);

Weitere Antworten (1)

Walter Roberson
Walter Roberson am 4 Okt. 2017

2 Stimmen

temp = repmat(str1, ceil(Count/length(str1))) ;
str3 = temp(1:Count);

2 Kommentare

temp = repmat(str1, 1, ceil(Count/length(str1))) ;
str3 = temp(1:Count);
Andrei Bobrov
Andrei Bobrov am 4 Okt. 2017
+1

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