How Can I replace specific lines in a text file
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I'm dealing with text files and I want to replace certain lines in the text. I do not know their location but I know the text in an above and a later line to those lines.
Example for that text
TABLE: "LINK PROPERTY DEFINITIONS 02 - LINEAR" Link="Rails Pinned" DOF=U1 Fixed=Yes Link="Rails Pinned" DOF=U2 Fixed=Yes
TABLE: "MASS SOURCE" MassSource=MSSSRC1 Elements=Yes Masses=Yes Loads=No IsDefault=Yes
TABLE: "MATERIAL PROPERTIES 04 - USER STRESS-STRAIN CURVES" Material="Timber Ties" Strain=-0.00078125 Stress=-1
I would like to replace the line/lines after TABLE: "MASS SOURCE" and before the following word TABLE: The word table repeats many times in the original text and because of that I need the following word TABLE: Is it possible?
Thank you
2 Kommentare
Cedric
am 22 Sep. 2017
What do you want to replace? There are plenty of tools for doing this, but we need to know exactly what you need to achieve. The best is to give a slice of this file with a few occurrences of what you need to replace, and to give an example of output after replacement.
Ahmed Rageh
am 22 Sep. 2017
Bearbeitet: Cedric
am 22 Sep. 2017
Akzeptierte Antwort
Here is an example, but we can be much more specific.
% - Read source.
content = fileread( 'myData.txt' ) ;
% - Update.
content = regexprep( content, 'TABLE:\s+"MASS SOURCE".*?(?=[\r\n]+TABLE)', 'Hello World' ) ;
% - Export update.
fId = fopen( 'myFile_updated.txt', 'w' ) ;
fwrite( fId, content ) ;
fclose( fId ) ;
where we use a regular expression for pattern matching. The call is
newContent = regexprep( oldContent, pattern, replacement ) ;
and the pattern matches a string
- starting with the literal TABLE:
- plus one or more + white space(s) \s
- plus the literal "MASS SOURCE"
- plus as few characters as possible .*? (lazy quantifier, when the greedy version .* means as many as possible)
- and then followed by (but not replaced, it's a look forward (?=...) ) one or more carriage return or line feed |[\r
7 Kommentare
Ahmed Rageh
am 22 Sep. 2017
My pleasure. I had a quick look at it and if I understand well, you want to
- Extract the table name "VEHICLES 3 - GENERAL VEHICLES 2 - LOADS" from the second file
- Find the corresponding table in the first file
- Replace the content from first file with content from second file.
If this is it, here is one way based on what I just explained:
originalFile = 'Original text.$2k.txt' ;
replacementFile = 'Text to replace.$2k.txt' ;
outputFile = 'Output.txt' ;
% - Extract table name from replacement file.
replacementContent = fileread( replacementFile ) ;
tableName = regexp( replacementContent, '(?<=TABLE:\s+")[^"]+', 'match', 'once' ) ;
% - Build pattern for matching what to replaced, based on the table name.
pattern = sprintf( 'TABLE:\\s+"%s.*?(?=[\\r\\n]TABLE)', tableName ) ;
% - Replace in original content.
originalContent = fileread( originalFile ) ;
originalContent = regexprep( originalContent, pattern, replacementContent ) ;
% - Export updated content.
fId = fopen( outputFile, 'w' ) ;
fwrite( fId, originalContent ) ;
fclose( fId ) ;
We extract the name by
- picking as many characters different from " as possible (not in the set of just " : [^'] )
- that follow the literal TABLE: followed by one or more white spaces followed by the literal ": (?<=...) is a look backward/behind, it tells the regexp engine to match something that is preceded by what is defined by the ....
Then we build the second pattern based on the name with SPRINTF. The only extra difficulty with respect to my first solution is that \ is a special character for SPRINTF ( formatSpec ), and must be doubled (because you want to produce the character \ in the pattern.
Finally, note that it is easy to loop through replacement files if you have many of them:
originalFile = 'Original text.$2k.txt' ;
replacementFiles = {'Rep1.txt', 'Rep2.txt', ...} ; % or the output of DIR.
outputFile = 'Output.txt' ;
originalContent = fileread( originalFile ) ;
for rfId = 1 : numel( replacementFiles )
replacementContent = fileread( replacementFiles{rfId} ) ;
tableName = regexp( replacementContent, '(?<=TABLE:\s+")[^"]+', 'match', 'once' ) ;
pattern = sprintf( 'TABLE:\\s+"%s.*?(?=[\\r\\n]TABLE)', tableName ) ;
originalContent = regexprep( originalContent, pattern, replacementContent ) ;
end
fId = fopen( outputFile, 'w' ) ;
fwrite( fId, originalContent ) ;
fclose( fId ) ;
Ahmed Rageh
am 22 Sep. 2017
I updated it for you, because it is starting to be a little more complex:
originalFile = 'Original text.$2k.txt' ;
replacementFile = 'Text to replace.$2k.txt' ;
outputFile = 'Output2.txt' ;
% - Read files, extract tables plus their content from replacement.
originalContent = fileread( originalFile ) ;
replacementContent = fileread( replacementFile ) ;
tables = regexp( replacementContent, 'TABLE.*?(?=\s*(TABLE|$))', 'match' ) ;
% - Iterate through replacements and update original content.
for pId = 1 : numel( tables )
% - Extract table name from replacement.
tableName = regexp( tables{pId}, '(?<=")[^"]+', 'match', 'once' ) ;
% - Build pattern for matching what to replace, based on the table name.
pattern = sprintf( 'TABLE:\\s+"%s.*?(?=\\s*(TABLE|END))', tableName ) ;
% - Replace in original content.
originalContent = regexprep( originalContent, pattern, ...
strtrim( tables{pId} )) ;
end
% - Export updated content.
fId = fopen( outputFile, 'w' ) ;
fwrite( fId, originalContent ) ;
fclose( fId ) ;
If you are facing many of these situations and think that investing in regular expressions for text pattern matching could be profitable, Mathworks wrote a nice section about them and I give the reference in the PS of this thread.
Ahmed Rageh
am 22 Sep. 2017
Cedric
am 22 Sep. 2017
Awesome! Please accept the answer if it helped.
Munish Sikka
am 30 Nov. 2019
Thanks for this wonderful answer.
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