# I want to obtain number of cases(matrix's length) . By applying same sum in any matrix. (on constraints)

3 views (last 30 days)
Brian Kim on 8 Sep 2017
Commented: Stephen23 on 13 Sep 2017
for example,
A is here.
A=[6 7 8 9];
and,
sumA=sum(A)=30;
The element of the matrix that causes the sum to be 30 must be expressed as a value between 4 and 12.
When I calculate directly, the number of cases that can be obtained is 3,4,5,6,7.
In this way, how to create code?
Stephen23 on 13 Sep 2017

José-Luis on 8 Sep 2017
If what you mean is that you want the sum of a random array of four elements to be thirty with some condition placed on the last of them:
lims = [4,12];
totVal = 30;
lastElement = randi(diff(lims) + 1,1 ) + lims(1) - 1;
valueToSplit = totVal - lastElement;
frac = rand(1,3);
frac = frac ./ sum(frac);
result = [round(frac.*valueToSplit), lastElement]
sum(result)

Andrei Bobrov on 8 Sep 2017
Edited: Andrei Bobrov on 13 Sep 2017
z = 4:12;
out = [];
for jj = 1:numel(z)
k = nchoosek(z,jj);
out = [out;num2cell(k(sum(k,2) == 30,:),2)];
end
"number of rows":
numel(out)
##### 2 CommentsShowHide 1 older comment
José-Luis on 12 Sep 2017
Edited: José-Luis on 13 Sep 2017
I don't understand what you mean. Could you explain?

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