I have a very basic newton's method that uses a loop and:
y = Jac(x)\(-F(x));
x = x + y;
to solve for the approximate solution.
Where x is a the initial guess in the form of a vector, F is the nonlinear function, and Jac is the jacobian matrix. Currently, I am inputting the jacobian by hand.
For example, system of equations =
2x(1) + x(2)
3x(1) + x(2)^2
=> Jac(x) =
[2, 1; 3, 2x(2)]
I was wondering if instead of solving it by hand if I could get Matlab to do it for me.

 Akzeptierte Antwort

Walter Roberson
Walter Roberson am 13 Apr. 2012

0 Stimmen

If you have the symbolic toolbox you can use the jacobian() function.

2 Kommentare

Jenn Lee
Jenn Lee am 14 Apr. 2012
is there a way to code this?
x = sym('x', [1 2]);
eqn = [2*x(1) + x(2)
3*x(1) + x(2)^2];
jacobian(eqn, x)

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

DIPANKAR POREY
DIPANKAR POREY am 7 Aug. 2019

1 Stimme

2x(1) + x(2)
3x(1) + x(2)^2
=> Jac(x) =
[2, 1; 3, 2x(2)]

1 Kommentar

This does not appear to be an answer? It appears to be a copy of part of the question.

Melden Sie sich an, um zu kommentieren.

Kategorien

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by