Subtracting Row and column vectors
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I need to subtract vectors of different dimensions, "A" with dimension of (1x91)double and "B" with dimension of (60x1) double. In addition, there are two more vectors "C" with dimension of (1x119) double and "D" with dimension of (119x1) double.
How can I get (X=A-B) and (Y=C-D) in such cases?
2 Kommentare
Akira Agata
am 13 Aug. 2017
What do you mean by 'X=A-B'?
X(1) = A(1) - B(1), ..., X(60) = A(60) - B(60) ?
If so, what about X(61) to X(91) ?
I need the detailed definition of your calculation rule of 'A-B' and 'C-D'.
Antworten (2)
Stephen23
am 13 Aug. 2017
Bearbeitet: Stephen23
am 13 Aug. 2017
One simple solution that does not require knowing anything about the sizes of the vectors:
>> A = randi(9,1,9)
A =
1 3 4 3 2 8 4 8 4
>> B = randi(9,6,1)
B =
7
4
8
7
4
2
>> C = diag(bsxfun(@minus,A,B))
ans =
-6
-1
-4
-4
-2
6
For newer MATLAB versions with implicit expansion:
diag(A-B)
Note that this is not particularly memory efficient so don't use this with large vectors!
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Akira Agata
am 17 Aug. 2017
I think the following would be one possible solution. By using zero-padding and transpose, I have adjusted A and B, C and D, to the same size.
%%Example of your data
A = rand(1,91);
B = rand(60,1);
% Adjut B to a row vector with the same length with A by zero padding
B1 = [B',zeros(1, length(A) - length(B))];
% Calculate X = A - B
X = A - B1;
%%Example of your data
C = rand(1,119);
D = rand(119,1);
% Adjust D to a row vector with the same length with C
D1 = D';
% Calculate Y = C - D
Y = C - D1;
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