First input argument must be a function handle.
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Sergio Manzetti
am 10 Aug. 2017
Kommentiert: Sergio Manzetti
am 10 Aug. 2017
Hi, I am trying to integrate using the following function:
if true
syms h g x pi
h = 2.0545
g = 5.3442
C = 1
y = C - (exp(-2.*g.*i.*x./h)).*(C - cos(x).*((h.^2)./2) + (g.*x)/2.*h.*i)
yx = integral(y,-pi,pi)
end
however, I get the error "First input argument must be a function handle. "
Can anyone suggest a solution?
Thanks!
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KSSV
am 10 Aug. 2017
h = 2.0545 ;
g = 5.3442 ;
C = 1 ;
y = @(x) C - (exp(-2.*g.*1i.*x./h)).*(C - cos(x).*((h.^2)./2) + (g.*x)/2.*h.*1i) ;
yx = integral(y,-pi,pi)
3 Kommentare
José-Luis
am 10 Aug. 2017
y = @(x) ((C - (exp(-2.*g.*i.*x./h)).*C) * ((C - (exp(-2.*g.*-i.*x./h)).*C);
In your anonymous function the @(x) is not the symbolic variable x.
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