Where is the issue in my "while" statement?

5 Ansichten (letzte 30 Tage)
Geo
Geo am 29 Jul. 2017
Beantwortet: Teja Muppirala am 30 Jul. 2017
I want to evaluate the first integer evenly divisible by 3 and 5 using a Matlab code. My attempt is the following:
n=1;
while mod(n,5)~=0 && mod(n,3)~=0
n=n+1;
end
n
I'm new to Matlab and wondering where the issue here is. The code returns n=3 for some reason. I also want to extend this to find the first number evenly divisible by 1-10, for which I wrote the following while loop which also did not return the expected value. Where is my error?
n=1;
while mod(n,1:10)~=0
n=n+1;
end
n
Thank you.
  3 Kommentare
Geo
Geo am 29 Jul. 2017
Bearbeitet: Geo am 29 Jul. 2017
Revision also not working as expected:
n=1;
for k=1:10
while mod(n,k)~=0
n=n+1;
end
end
n
Walter Roberson
Walter Roberson am 29 Jul. 2017
found_solution = false;
n = 0;
while ~found_solution
n = n + 1;
found_solution = true;
for k = 1 : 10
if mod(n,k) ~= 0
found_solution = false;
break;
end
end
end
n

Melden Sie sich an, um zu kommentieren.

Antworten (2)

the cyclist
the cyclist am 29 Jul. 2017
Bearbeitet: the cyclist am 29 Jul. 2017
In your second case, you are doing
mod(1,1)
then
mod(2,2)
then
mod(3,3)
and so on, because you are always incrementing n right along with k. Those mod functions are always equal to zero, so they always satisfy the while condition, so you get to n = 10.

Teja Muppirala
Teja Muppirala am 30 Jul. 2017
You were on the right track. This gives 2520:
n=1;
while any( mod(n,1:10)~=0 )
n=n+1;
end
n
When your conditional has more than one element, all of them must be true for it to evaluate as true. This will return 'B' and 'C'.
if [1 1 1 0]
disp('A')
else
disp('B')
end
if [1 1 1 1]
disp('C')
else
disp('D')
end

Kategorien

Mehr zu Graphics Object Programming finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by