Repeating elements in a matrix.

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Gratitude Kim
Gratitude Kim am 27 Jul. 2017
Kommentiert: Gratitude Kim am 27 Jul. 2017
A=zeros(3,4)
A =
0 0 0 0
0 0 0 0
0 0 0 0
>> [nRows,nCols] = size(A); A(1:(nRows+1):nRows*nCols) = 1
A =
1 0 0 0
0 1 0 0
0 0 1 0
Appreciate your kind assistance on how can I write so that my matrix becomes :
A=[1 1 0 0; 0 1 1 0; 0 0 1 1]
Thanks

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Andrei Bobrov
Andrei Bobrov am 27 Jul. 2017
Bearbeitet: Andrei Bobrov am 27 Jul. 2017
A=zeros(3,4);
n = size(A,1);
A([1:n+1:end,n+1:n+1:end]) = 1
or
t = true(3,4);
out = tril(t,1) & triu(t);

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