And I'm hoping for a solution without loops since my actual p matrix is 1000*1000, so I'd want the same behavior to replicate across rows of p. E.g. if p(2,1)=1, then z(2,1)=1, if p(2,2)=4, then z(2,2)=16.
Indexing one matrix using elements of another
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Garima Sharma
am 18 Jul. 2017
Kommentiert: Garima Sharma
am 18 Jul. 2017
I have a matrix p=[1,2,4] and want to retrieve elements of another matrix u =[1,11,7;2,3,5;9,10,8;15,16,17], using the column of p combined with its entry e.g. I want a matrix z=[1,3,17]
z(1,1) = u(entry in p(col1), 1); z(1,2) = u(entry in p(col2),2); z(1,3)=u(entry in p(col3), 3).
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the cyclist
am 18 Jul. 2017
Bearbeitet: the cyclist
am 18 Jul. 2017
z = u(sub2ind(size(u),p,1:numel(p)))
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