how to find the equivalent resistance of two resistors in parallel and series
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help me finding the equivalent resistance of two resistors for example r1 and r2 in parallel and series
clc;
clear all;
r1=1200;
r2=1000;
rt=parallel(r1,r2);
display('rt')
when i run this code i am getting either answer ams as 1 or some error
Antworten (2)
dbmn
am 18 Jul. 2017
parallel might not be the best function to use here. See more in the documentation (which is what you should do everytime you use a function either by typing help parallel or doc parallel)
sys = parallel(sys1,sys2)
% Which needs sys, sys1 and sys2 in a state space notation to work
but why bother writing these in that special state space notation when you can simply use Wikipedia and Google
rt = r1*r2 / (r1+r2);
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Andrei Bobrov
am 18 Jul. 2017
Bearbeitet: Andrei Bobrov
am 18 Jul. 2017
r1=1200;
r2=1000;
parallel = @(r1,r2)1/sum(1./[r1,r2]); % or: parallel = @(r1,r2)prod([r1,r2])/sum([r1,r2]);
rt=parallel(r1,r2)
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