scatterplot

is there any way to get the (x,y) coordinates of a scatterplot.

Answer 1

[Andrew Newell]

You have to dig down a couple of layers to find the data:

h = scatterplot(rand(20,2));
h = get(h,'Children');
h = get(h,'Children');
x = get(h,'xdata');
y = get(h,'ydata');

Answer 2

[Tasos Giannoulis]

SCATTERPLOT returns a handle to the figure. The child of the figure is the "Axes", whose child is a "Line" (even though the Line object has markers only, with no lines connecting them). The Line object has the X and Y values:

h = scatterplot(awgn(2*randi([0 1], 10, 1)-1, 20));
x = h.Children.Children.XData;
y = h.Children.Children.YData;

While this answers the question, I wonder why you want to get the XData/YData from the plot, given that these were the input of the SCATTERPLOT function at the first hand. You can separate the complex number to its real and imaginary parts using the REAL and IMAG functions.

If you were looking for the coordinates of the figure window instead, you can use:

h.Position

Answer 3

[Walter Roberson]

get() the XData and YData properties from the plot handle.

[jessica david]

i tried

>> h = gcf;

>> scatterplot(y)

>> x = get(h,'xdata');

but it gives an error saying

??? Error using ==> get

There is no 'xdata' property in the 'figure' class.

[Matt Fig]

Xdata is a property of the plotted object, not a figure object. I don't know about the SCATTERPLOT function, but this works for PLOT:

L = plot(1:10);

get(L,'xdata')

[Matt Fig]

According to the doc, SCATTERPLOT returns the handle to the figure, which seems very strange to me. However, you might still be able to find the data with FINDALL.

H = findall(0,'type','line')

and if this doesn't find it, you will have to call FINDALL with only the 0 and look at each element of H to find which one has the data.