Extract group of identical values from an array

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Sugyani Mahapatra
Sugyani Mahapatra am 7 Jul. 2017
I have the array
a = [0 0 0 1 1 1 0 0 0 0 0 1 1 1 1 0 0 1 1];
I want to extract the first and last index where a==1 as a group
o/p: [4 6; 12 15; 18 19];
Is there any efficient way to do this?
  1 Kommentar
Adam
Adam am 7 Jul. 2017
Bearbeitet: Adam am 7 Jul. 2017
firstIndices = find( diff(a) == 1) + 1;
lastIndices = find( diff(a) == -1);
will give you most of what you need, but you would need to make a special case for the last index which it will not find, and obviously it is more efficient to do the diff just once, etc. Shaping the results into the format you want shouldn't be difficult.

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José-Luis
José-Luis am 7 Jul. 2017
If you have the image-processing toolbox.

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C.J. Harris
C.J. Harris am 7 Jul. 2017
a = [0 0 0 1 1 1 0 0 0 0 0 1 1 1 1 0 0 1 1];
nStart = find(diff([0 a 0]) == 1);
nEnd = find(diff([0 a 0]) == -1) - 1;
nResult = [nStart' nEnd'];

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