My function is: funk1=3*((1-x).^2)*exp(-x.^2-(y+1).^2) and matlab send me and error but don't write where it is.

5 Kommentare

KSSV
KSSV am 30 Mai 2017
Show the full code.....
Dennis Semke
Dennis Semke am 30 Mai 2017
x=linspace(-3,3,49); y=linspace(-3,3,49); funk1=3*((1-x).^2)*exp(-x.^2-(y+1).^2); mesh(funk1)
It works for me:
>> x = 2;
>> y = 3;
>> 3*((1-x).^2)*exp(-x.^2-(y+1).^2)
ans = 6.1835e-009
Whatever you are doing is causing an error.
Dennis Semke
Dennis Semke am 30 Mai 2017
hm i dont know why because matlab send me everytime the error 'Error in matlab_blatt6_1 (line 3) funk1=3*((1-x).^2)*exp(-x.^2-(y+1).^2)
so i cant meshplot it...
KSSV
KSSV am 30 Mai 2017
YOu can mesh plot it..look at my answer....it is a mesh plot.

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 Akzeptierte Antwort

Stephen23
Stephen23 am 30 Mai 2017
Bearbeitet: Stephen23 am 30 Mai 2017

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F = 3*((1-x).^2).*exp(-x.^2-(y+1).^2);
^ you need this .
Read about the difference here:

Weitere Antworten (3)

KSSV
KSSV am 30 Mai 2017

0 Stimmen

x=linspace(-3,3,49);
y=linspace(-3,3,49);
[X,Y] = meshgrid(x,y) ;
funk1=3*((1-X).^2).*exp(-X.^2-(Y+1).^2);
surf(X,Y,funk1)
Rik
Rik am 30 Mai 2017

0 Stimmen

The error explains exactly what is wrong: "Error using * Inner matrix dimensions must agree."
You forgot the dot for element-wise multiplying before the exp.
x=linspace(-3,3,49);
y=linspace(-3,3,49);
funk1=3*((1-x).^2).*exp(-x.^2-(y+1).^2);
Dennis Semke
Dennis Semke am 30 Mai 2017

0 Stimmen

Ou ok now it works. Big ty :) I rly dont saw it and made me angry :'D

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